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UPSC NDA I 2012 Mathematics Paper
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© examsnet.com
Question : 45
Total: 120
What is the value of
sin
(
1920
∘
)
?
1
2
1
√
2
√
3
2
1
3
Validate
Solution:
s
i
n
(
1920
∘
)
s
i
n
(
360
×
5
+
120
∘
)
s
i
n
120
∘
s
i
n
(
90
∘
+
30
∘
)
cos
30
∘
=
√
3
2
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