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UPSC NDA I 2014 Mathematics Paper
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© examsnet.com
Question : 57
Total: 120
What is the equation of the line through (1, 2) so that the segment of the line intercepted between the axes is bisected at this point?
[NDA I 2014]
2
x
−
y
=
4
2
x
−
y
+
4
=
0
2
x
+
y
=
4
2
x
+
y
+
4
=
0
Validate
Solution:
Let equation be
x
a
+
y
b
=
1
Intercept points A(a,0) and B(0,b)
The mid point of AB is (1,2),then
1
=
a
+
0
2
and
2
=
0
+
b
2
⇒
a
=
2
and
b
=
4
The equation is
x
2
+
y
4
=
1
⇒
2
x
+
y
−
4
=
0
© examsnet.com
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