x and y are positive numbers x≤y2 Reflexive- x≤x2∀ positive numbers Hence relation is reflexive Transitive- x≤y2y≤z2 Let x=5,y=3,z=2 5≤(3)2(3)≤(2)2 but 5≮(2)2 Hence x≤y2y≤z2 x≰z2 Thus relation is not transitive Symmetric 1≤(2)2 while 2≰(1)2 Hence relation is not symmetric. Thus x≤y2∀ positive number is reflexive,but not transitive and symmetric