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UPSC NDA I 2016 Mathematics Solved Paper

For the next two (2), items that· follow :

Consider the two lines

x+y+1=0

and

3x+2y+1=0

Equations of lines

x+v+1=0

3x+2y+1=0

3x+3y+3=0

3x+2y+1=0

-\;\;-\;\;\;-\;\;\;\;-

––––––––––––––

y=-2

x=1

Points of intersection

(1,-2)

[NDA I 2016]

Question : 43 of 120

Marks: +1, -0

Solution:

Equations of lines

x+v+1=0

3x+2y+1=0

3x+3y+3=0

3x+2y+1=0

-\;\;-\;\;\;-\;\;\;\;-

––––––––––––––

y=-2

x=1

Points of intersection

(1,-2)

Equation of y-axis

x=0

Equation of line parallel to y-axis is

x=k

If this line passes through (

1,-2

then)

x=1

Hence equation of line which passes through point of intersection of given line (1, - 2) and parallel to y-axis

x=1

\Rightarrow x-1=0

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