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UPSC NDA I 2017 Mathematics Solved Paper
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© examsnet.com
Question : 13
Total: 120
If B is a non-singular matrix and A is a square matrix, then the value of
d
e
t
(
𝐵
−
1
𝐴
𝐵
)
is equal to
[NDA I 2017]
d
e
t
(
𝐵
)
d
e
t
(
𝐴
)
d
e
t
(
B
−
1
)
d
e
t
(
A
−
1
)
Validate
Solution:
|
B
−
1
A
B
|
=
|
B
−
1
|
|
A
|
|
B
|
=
1
|
B
|
|
A
|
|
B
|
=
|
A
|
© examsnet.com
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