Concept:For an odd function f(x), the integral over a symmetric interval [−a,a] is zero: ∫−aaf(x)dx=0.Explanation:Let f(x)=sinx−tanx.Evaluate f(−x): f(−x)=sin(−x)−tan(−x)=−sinx−(−tanx)=−sinx+tanx=−(sinx−tanx)=−f(x).Since f(−x)=−f(x), the function f(x) is odd.The integration limits are from −4π to 4π, which is symmetric about zero.For an odd function integrated over a symmetric interval, the net area cancels out, so the value of the integral is 0.Answer:0 (Option C).