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UPSC NDA I 2019 Mathematics Solved Paper
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© examsnet.com
Question : 29
Total: 120
The straight lines x+ y−4=0, 3 x+ y−4=0 and x+3 y−4=0 , from a triangle, which is
[NDA I 2019]
isosceles
right-angled
equilateral
scalene
Validate
Solution:
👈: Video Solution
(A)
Let the slope of the lines be
m
1
= −1,
m
2
= −3 and
m
3
=
−
1
3
Angle between lines
L
1
and
L
2
is tan
θ
1
=
|
−
1
+
3
1
+
3
|
=
1
2
Angle between lines
L
1
and
L
3
is tan
θ
2
=
|
−
1
+
1
3
1
+
1
3
|
=
1
2
Angle between lines
L
2
and
L
3
is tan
θ
2
=
|
−
3
+
1
3
1
+
1
|
=
4
3
Hence triangle is isosceles
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