Concept:Integration by parts and the logarithmic property ln(x2)=2lnx.Explanation:First, simplify the integral using ln(x2)=2lnx.Thus, ∫ln(x2)dx=∫2lnxdx=2∫lnxdx.Now, integrate ∫lnxdx using integration by parts with u=lnx and dv=dx.Then du=x1dx and v=x.Apply the formula: ∫udv=uv−∫vdu.So ∫lnxdx=xlnx−∫x⋅x1dx=xlnx−∫1dx=xlnx−x+c.Multiply by 2: 2(xlnx−x)+c=2xlnx−2x+c.Therefore, ∫ln(x2)dx=2xlnx−2x+c.Answer:2xlnx−2x+c (Option A)