Concept:Parametric differentiation: if x=f(t) and y=g(t), then dydx=g′(t)f′(t) or its reciprocal.Explanation:Given x=etcost and y=etsint.Differentiate x with respect to t: dtdx=etcost−etsint.Differentiate y with respect to t: dtdy=etsint+etcost.Now compute dxdy=dx/dtdy/dt=etcost−etsintetsint+etcost.At t=0: numerator =e0(sin0+cos0)=1(0+1)=1, denominator =e0(cos0−sin0)=1(1−0)=1. Hence dxdy=1.Therefore dydx=dy/dx1=1.Answer:1 (Option B)