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UPSC NDA I 2023 Mathematics Solved Paper

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Consider the following for the next two (02) items that follow :
Let x=sin2A+sinA+1sinAx=\frac{\sin^2 A + \sin A + 1}{\sin A} where 0<Aπ20 < A \leq \frac{\pi}{2}
[NDA I 2023]
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