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UPSC NDA I 2023 Mathematics Solved Paper

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Consider the following for the next two (02) items that follow :

Given that

m(\theta)=\cot^2 \theta+n^2 \tan^2 \theta+2 n

where

n

is a fixed positive real number.

[NDA I 2023]

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Question : 54 of 120

Marks: +1, -0

Under what condition does

m

attain the least value?

$n=\tan^2 \theta$
$n=\cot^2 \theta$
$n=\sin^2 \theta$
$n=\cos^2 \theta$

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