What is \sin (\\alpha+1^\circ)+\cos (\\beta+1^\circ) equal to? [NDA-I 2020]

Correct Answer is : 1√2(√3cos1°+sin1°)

\sqrt{3} \cos 1^\circ+\sin 1^\circ

\sqrt{3} \cos 1^\circ-\frac{1}{2} \sin 1^\circ

1/\sqrt2(\sqrt{3} \cos 1^\circ- \sin 1^\circ)

1/\sqrt2(\sqrt{3} \cos 1^\circ+ \sin 1^\circ)

Correct Answer is : 1√2(√3cos1°+sin1°)

Test Index

UPSC NDA I and II 2020 Math Solved Paper

DIRECTIONS (Qs. 22-24) : Read the following information and answer the three items that follow:
Let α=β=15°

[NDA-I 2020]

Question : 24 of 120

Marks: +1, -0

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