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UPSC NDA II 2010 Mathematics Paper
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© examsnet.com
Question : 14
Total: 120
What is the value of
|
1
ω
2
ω
2
2
2
ω
2
4
ω
3
3
3
ω
3
6
ω
4
|
where
ω
is the cube root of unity?
0
1
2
3
Validate
Solution:
|
1
ω
2
ω
2
2
2
ω
2
4
3
3
6
ω
|
(
∴
ω
3
=
1
)
1
(
4
ω
−
4
ω
4
)
−
2
(
6
ω
2
−
6
ω
2
)
+
3
(
4
ω
−
4
ω
4
)
1
(
4
ω
−
4
ω
)
−
2
(
6
ω
2
−
6
ω
2
)
+
3
(
4
ω
−
4
ω
)
=
0
© examsnet.com
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