The given equation (x−a)(x−b)=c can be written as x2−(a+b)x+(ab−c)=0 . . . (i) ∵α,β are the roots of the equation .∴α+β=a+b αβ=ab−c} . . . (ii) If λ and δ are the roots of equation (x−α)(x−β)+c=0 x2−(α+β)x+(αβ+c)=0 λλ+δ=α+β=a+b and λ.δ=αβ+c=ab by ... (ii) Clearly, the roots λ and δ are a and b.