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UPSC NDA II 2025 Mathematics Paper

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Question Numbers: 29-30
For the following two (02) items:
Let cos(2x+3y)=  12\cos(2x+3y) = \;\frac{1}{2} and cos(3x+2y)=  32\cos(3x+2y) = \;\frac{\sqrt{3}}{2}  where  π<(2x+3y)<π-\pi < (2x+3y) < \pi and π<(3x+2y)<π.-\pi < (3x+2y) < \pi .
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