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UPSC NDA Math Model Paper 1
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© examsnet.com
Question : 92
Total: 120
The logarithm of
1
256
to the base
2
√
2
is:
8
3
−
16
3
−
14
3
−
8
3
Validate
Solution:
Let's say
log
2
√
2
1
256
=
x
⇒
(
2
√
2
)
x
=
1
256
⇒
2
3
x
∕
2
=
2
−
8
⇒
3
2
x
=
−
8
⇒
x
=
−
16
3
© examsnet.com
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