For no consonants to be together the word can be formed as '1' A '2' I '3' O '4', where 1, 2, 3, 4 are the places where 2 consonants P and N could be placed ∴ Vowels arranged in = 3! ways Ways of arranging consonants =4P2 The total number of ways formed N=3!×4P2 N=6×12=72