Here, Let A = (0,2,2), B = (2,0,-1) and C =(3,4,0)
AB = (2-0, 0-2, -1-2) = (2, -2, -3) and
AC = (3-0, 4-2, 0-2) = (3, 2, -2)
Area of triangle
=×|× =|| =|[(4+6)+(−4+9)+(4+6)]| =1∕2(10i+5j+10k) =1∕2√(100+25+100) = 15/2 sq unit
Hence, option (1) is correct.