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UPSC NDA Math Model Paper 10
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© examsnet.com
Question : 87
Total: 120
10
π
∫
0
|
sin
x
|
d
x
20
8
10
18
Validate
Solution:
I
=
10
π
∫
0
|
sin
x
|
d
x
∵
|
sin
x
|
is periodic with period
π
and
sin
x
>
0
if
0
<
x
π
, we can write:
=
10
10
π
∫
0
|
sin
x
|
d
x
=
10
10
π
∫
0
sin
x
d
x
=
10
[
−
cos
x
]
0
π
=
20
© examsnet.com
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