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UPSC NDA Math Model Paper 2
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© examsnet.com
Question : 54
Total: 120
The sum of the focal distances of any point on the ellipse se
x
2
a
2
+
y
2
b
2
=
1
,
a
<
b
, with eccentricity e, is given by:
2ae
2b
2a
2be
Validate
Solution:
Using the above formula, the focal distances of a point P(x, y) on the ellipse are b + ey and b - ey, since a < b.
The sum of these distances is: b + ey + b - ey = 2b.
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