We observe that ax5 and bx3 are odd functions of x, because a(−x)5=−ax5 and b(−x)3=−bx3. ∴−2∫2ax5dx=0 and −2∫2bx3dx=0 The value of −2∫2(ax5+bx3+c)dx depends on the value of c. In fact, −2∫2(ax5+bx3+c)dx−2∫2cdx=c[x]−22=c[2−(−2)]=4c=c[x]−22=c[2−(−2)]=4c