Given, ​1t−11​t−111​11t−1​​=0⇒1[1⋅(t−1)−1]−(t−1)[(t−1)2−1]+1[(t−1)−1]=0⇒(t−2)−(t−1)(t2−2t)+(t−2)=0⇒2(t−2)−t(t−1)(t−2)=0⇒(t−2)(2−t2+t)=0⇒(t−2)(t2−t−2)=0⇒(t−2)(t−2)(t+1)=0⇒(t−2)2(t+1)=0⇒t=2,−1 The roots of the equation ​1t−11​t−111​11t−1​​ = 0 are -1, 2