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UPSC NDA Math Model Paper 4
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© examsnet.com
Question : 12
Total: 120
Find the equation of the normal to the curve
2
x
2
=
y
,
which passes through (1, 2)
x + y + 9 = 0
4x + y - 9 =0
3x + 4y - 8 = 0
x + 4y - 9 = 0
Validate
Solution:
Here,
y
=
2
x
2
d
y
d
x
=
4
x
d
y
d
x
|
x
=
1
=
4
Slope of normal to the curve
=
−
1
(
d
y
d
x
)
=
−
1
∕
4
Equation of normal to curve passing through (1,2) is
y
−
2
=
−
1
∕
4
(
x
−
1
)
⇒
4
y
−
8
=
−
x
+
1
⇒
x
+
4
y
−
9
=
0
Hence, option (4) is correct.
© examsnet.com
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