Given series is 2, 6, 10, ...,146 First term, a = 2, last term, an=14 6, an Common difference d = 4, so it is an AP an=a+(n–1)d 146 = 2 + (n - 1) (4) ⇒ n - 1 = 144/4 ⇒ n = 36 + 1 = 37 So, number of terms in given series = 37 Middle term = (37 + 1)/2 = 19th term a19=2+(19−1)×4 = 2 + 72 = 74 Hence, option (3) is correct.