Given f(x)â=â2x3â3x2â12x+6 As we know that Point c from the domain of the function y = f(x) is called stationary point of the function y =f(x)âifâfâ˛(c)=0 First find fâ˛(x). fâ˛(x)=â6x2ââ6xâ12 Now, fâ(x)=0 â6x2â6xâ12=0 â(xâ2)(x+1)=0 â x = 2 and x = - 1 â´ Stationary point of the function are 2 and -1
