The equation of straight line passing through the point (x1,y1) is given by,(y−y1)=m(x−x1), where m is slope of the line. The equation of straight line passing through the point (1,−2) is given by, (y+2)=m(x−1) ....(1) The equation of straight line passing through the point (1, -2) and parallel to the line y = 5x - 2 ⇒ Slope of the line y = 5x - 2 is m = 5. The slope of the parallel lines are equal. So slope of the required line is m = 5 Equation (1) becomes ⇒ (y + 2) = 5(x − 1)