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UPSEE 2017 Solved Paper
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© examsnet.com
Question : 14
Total: 150
In steady state, charge on
3
µ
F
capacitor is
36
µ
C
27
µ
C
18
µ
C
54
µ
C
Validate
Solution:
We can redraw the above circuit diagram as following
Value of current in the circuit,
i
=
V
R
e
q
i
=
18
6
+
6
=
1.5
A
Voltage drop across
R
2
,
V
2
=
R
2
i
=
6
×
1.5
=
9
V
Charge on capacitor
(
C
2
=
3
µ
F
)
is
q
2
=
C
2
V
2
=
3
×
9
=
27
µ
C
© examsnet.com
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