Let I1 is current flowing through first loop. ∴ I1=
2
3+2
=
2
5
A
and I2 is current flowing through the second loop. ∴I2=
4
3+5
=
1
2
A Let VA is potential of point A and VB is potential of point B. Now, we apply Kirchhoff's law between points A and B, ∴VA−3I1−4+3I2=VB ⇒VA−VB=3×