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UPSEE 2018 Solved Paper
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© examsnet.com
Question : 47
Total: 150
A long rigid wire lies along the X-axis and carries a current of
10
A
in the positive
x
-direction. Round the wire external magnetic field is
B
=
^
i
+
2
x
2
^
j
with
x
in metres and
B
in tesla. The magnetic force (in SI units) on the segment of the wire between
x
=
1
m
and
x
=
4
m
is
1260
1280
3
1310
420
Validate
Solution:
Given,
i
=
10
A
,
length of the wire between,
x
=
4
m
and
x
=
1
m
,
i
=
4
−
1
=
3
m
can be written as
at
x
=
1
m
,
B
1
=
^
i
+
2
^
j
x
=
4
m
,
B
2
=
^
i
+
2
×
4
2
^
j
=
^
i
+
32
^
j
As we know, magnetic force.
F
=
^
i
(
l
+
B
)
After solving,
F
=
420
N
© examsnet.com
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