Concept:The sum of squares of the first n natural numbers can be calculated using a standard formula.Explanation:Use the formula: Sum=6n(n+1)(2n+1)Here, n=10.Substitute the values: Sum=610×(10+1)×(2×10+1)Simplify inside: 10×11×21Multiply: 10×11=110 and 110×21=2310Divide by 6: 2310÷6=385Answer:Option D, 385