Test Index

VITEEE 2009 Paper

Question : 59 of 120

Marks: +1, -0

\mathrm{SO}_2

\mathrm{SO}_3

gas?

Solution:

30% solution of

\mathrm{H}_2\mathrm{O}_2

is known as perhydrol.

\mathrm{H}_2\mathrm{O}_2

decomposes as

2\mathrm{H}_2\mathrm{O}_2 \rightarrow 2\mathrm{H}_2\mathrm{O} + \mathrm{O}_2

Volume strength of 30%

\mathrm{H}_2\mathrm{O}_2

solution is 100 i.e., 1 ml. of this solution on decomposition gives 100 ml. oxygen.

\mathrm{SO}_{\underset{\text{1L}}{2}} + \frac{1}{2}\mathrm{O}_{\underset{\text{1/2L}}{2}} \longrightarrow \mathrm{SO}_{\underset{\text{1L}}{3}}

2\mathrm{L}\;\;\;\;\;\;\;1\mathrm{L}\;\;\;\;\;\;\;\;\;2\mathrm{L}

Since, 100 ml of oxygen is obtained by = 1 ml of

\mathrm{H}_2\mathrm{O}_2

∴ 1000 ml of oxygen will be obtained by =

\frac{1}{100} \times 1000

ml of

\mathrm{H}_2\mathrm{O}_2

= 10 ml of

\mathrm{H}_2\mathrm{O}_2

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