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VITEEE 2011 Paper
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Section:
Chemistry
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© examsnet.com
Question : 67
Total: 120
20 mL of 0.2 M NaOH is added to 50 mL of 0.2 M acetic acid. The pH of this solution after mixing is
(
K
a
= 1.8 x
10
−
5
)
4.5
2.3
3.8
4
Validate
Solution:
NaOH +
C
H
3
C
O
O
H
→
C
H
3
C
O
O
N
a
+
H
2
O
m
‌
mol
20
×
0.2
50
×
0.2
0
0
added
=
4
=
10
m
‌
mol
‌
after
‌
reaction
0
6
4
4
[
C
H
3
C
O
O
H
]
=
6
70
:
[
C
H
3
C
O
O
N
a
]
=
4
70
Now since for a basic buffer
pH = - log
k
a
+ log
[
salt
]
[
base
]
∴ pH = - log (1.8 ×
10
−
5
) + log
4
∕
70
6
∕
70
= 4.56
© examsnet.com
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