Test Index

VITEEE 2011 Paper

Section: Chemistry

Question : 79 of 120

Marks: +1, -0

Solution:

Gas (Y)

\mathrm{SO}_2

which can be obtained from

\mathrm{Na}_2\mathrm{SO}_3

(A) and gas (Z) is

\mathrm{H}_2\mathrm{S}

which can be obtained from

\mathrm{Na}_2\mathrm{S}

(B).

This can be easily understood by the following reactions.

\underset{\mathrm{(A)}}{\mathrm{Na}_2\mathrm{SO}_3}

+ 2 HCl → 2NaCl +

\underset{\mathrm{(Y)}}{\mathrm{SO}_2}

\mathrm{H}_2\mathrm{O}

\underset{\mathrm{(B)}}{\mathrm{Na}_2\mathrm{S}}

+ 2 HCl → 2NaCl +

\underset{\mathrm{(Z)}}{\mathrm{H}_2\mathrm{S}}

\mathrm{K}_2\mathrm{Cr}_2\mathrm{O}_7

\mathrm{H}_2\mathrm{SO}_4

3\mathrm{SO}_2

→

\mathrm{K}_2\mathrm{SO}_4 + \mathrm{Cr}_2(\mathrm{SO}_4)_3 + \mathrm{H}_2\mathrm{O}

\mathrm{pb}(\mathrm{CH}_3\mathrm{COO})_2 + \mathrm{H}_2\mathrm{S}

→

\underset{\text{black}}{\mathrm{PbS}}

↓ +

2\mathrm{CH}_3\mathrm{COOH}

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