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VITEEE 2012 Paper

Section: Chemistry

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Question : 41 of 120

Marks: +1, -0

A bubble of air is underwater at temperature 15°C and the pressure 1.5 bar. If the bubble rises to the surface where the temperature is 25 °C and the pressure is 1.0 bar, what will happen to the volume of the bubble ?

Volume will become greater by a factor of 1.6
Volume will become greater by a factor of 1.1
Volume will become smaller by a factor of 0.70
Volume will become greater by a factor of 2.9

Solution:

Since

\frac{P_1V_1}{T_1}

=

\frac{P_2V_2}{T_2}

(By ideal gas equation)

or

\frac{1.5 \times V_1}{288}

=

\frac{1 \times V_2}{298}

∴

V_2

= 1.55

V_1

i.e, volume of bubble will be almost 1.6 times to initial volume of bubble.

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