Area of the coil A=5cm2=5×10−4m2 Number of turns N=20 Magnetic field B=103 Gauss =10−1T Angle between magnetic field and normal to the plane of coil θ=30∘ Thus flux through the coil φ=NBA‌cos‌θ ∴φ=20×10−1×5×10−4×0.865=8.65×10−4Wb