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VITEEE 2015 Paper

Section: Physics

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Question : 9 of 120

Marks: +1, -0

The input resistance of a common emitter amplifier is 330 Ω and the load resistance is 5 k Ω . A change of base current is 15 µA results in the change of collector current by 1mA. The voltage gain of amplifier is

1000
10001
1010
1100

Solution:

Given: Δ

I_C

= 1 mA =

10^{-3}

A

Δ

I_b

= 15 µA = 15 ×

10^{-6}

A

R_L

= 5kΩ = 5 ×

10^{3}

Ω

R_i

= 330 Ω

The voltage gain of an amplifier

A_r

=

\frac{\Delta L_C \times R_L}{\Delta L_b \times R_i}

=

\frac{10^{-3} \times 5 \times 10^{3}}{15 \times 10^{-6} \times 330}

= 1010

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