Let I = a∫b​ x f (x) dx Let a + b - x = z ⇒ - dx = dz When x = a , z = b and when x = b , z = a ∴ I = - b∫a​ (a + b - z) f (z) dz I = (a + b) b∫a​ f (x) dx - a∫b​ x f (x) dx I = (a + b) b∫a​ f (x) dx - 1 ; 2I = (a + b) a∫b​ f (x) dx I = (2a+b​)a∫b​ f (x) dx