Exams Net
Unrestricted Exams Practice
Home
Exams
Banking
CUET
Defence
Engineering
Finance
GATE
Insurance
International
JEE
LAW
MBA
MCA
Medical
Other
Police
PSC
RRB
SSC
State Govt
Subjectwise
Teacher
SET Exams
UPSC
Aptitude
Algebra and Higher Mathematics
Arithmetic
Commercial Mathematics
Data Based Mathematics
Geometry and Mensuration
Number System and Numeracy
Problem Solving
Board Exams
Andhra
Bihar
CBSE
Gujarat
Haryana
ICSE
Jammu and Kashmir
Karnataka
Kerala
Madhya Pradesh
Maharashtra
Odisha
Tamil Nadu
Telangana
Uttar Pradesh
English
Competitive English
CBSE
CBSE Class 10 Solutions
CBSE Class 12 Solutions
CBSE Question Papers (Pdf)
NCERT Books (Pdf)
NCERT Exemplar Books (Pdf)
NCERT Study Notes (Pdf)
CBSE Study Concepts (Pdf)
NCERT Text Book Class 11 Solutions
NCERT Text Book Class 12 Solutions
ICSE Class 10 Papers
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Contact Us
Our Apps
Privacy
+
-
Test Index
VITEEE 2017 Paper
Show Para
Hide Para
Section:
Chemistry
Share question:
© examsnet.com
Question : 52 of 125
Marks:
+1
,
-0
1 -Propanol and 2-propanol can be distinguished by
oxidation with alkaline
K
M
n
O
4
\mathrm{KMnO_4}
KMn
O
4
followed by reaction with Fehling solution
oxidation with acidic dichromate followed by reaction with Fehling solution
oxidation by heating with copper followed by reaction with Fehling solution
oxidation with concentrated
H
2
S
O
4
\mathrm{H_2SO_4}
H
2
S
O
4
followed by reaction with Fehling solution
Validate
Solution:
C
H
3
C
H
2
C
H
2
O
H
\mathrm{CH_3CH_2CH_2OH}
C
H
3
C
H
2
C
H
2
OH
→
or
K
2
C
r
2
O
7
/
H
+
alk.
K
M
n
O
4
\xrightarrow[\text{or } \mathrm{K_2Cr_2O_7}/\mathrm{H}^{+}]{\text{alk. } \mathrm{KMnO_4}}
alk.
KMn
O
4
or
K
2
C
r
2
O
7
/
H
+
C
H
3
C
H
2
C
H
O
\mathrm{CH_3CH_2CHO}
C
H
3
C
H
2
CHO
→
C
H
3
C
H
2
C
O
O
H
\mathrm{CH_3CH_2COOH}
C
H
3
C
H
2
COOH
→
Felhing soln
\xrightarrow{\text{Felhing soln}}
Felhing soln
No reaction
(b)
C
H
3
C
H
O
C
H
3
\mathrm{CH_3CHOCH_3}
C
H
3
CHOC
H
3
→
or
K
2
C
r
2
O
7
/
H
+
alk.
K
M
n
O
4
\xrightarrow[\text{or } \mathrm{K_2Cr_2O_7}/\mathrm{H}^{+}]{\text{alk. } \mathrm{KMnO_4}}
alk.
KMn
O
4
or
K
2
C
r
2
O
7
/
H
+
C
H
3
C
O
C
H
3
\mathrm{CH_3COCH_3}
C
H
3
COC
H
3
→
C
H
3
C
O
O
H
\mathrm{CH_3COOH}
C
H
3
COOH
→
Feh sol.
\xrightarrow{\text{Feh sol.}}
Feh sol.
No reaction
(c)
C
H
3
C
H
2
C
H
2
O
H
\mathrm{CH_3CH_2CH_2OH}
C
H
3
C
H
2
C
H
2
OH
→
C
u
\xrightarrow{\mathrm{Cu}}
Cu
C
H
3
C
H
2
C
H
O
\mathrm{CH_3CH_2CHO}
C
H
3
C
H
2
CHO
→
Fehling solution
\xrightarrow{\text{Fehling solution}}
Fehling solution
C
u
2
O
\mathrm{Cu_2O}
C
u
2
O
(red)
C
H
3
C
H
O
H
C
H
3
\mathrm{CH_3CHOHCH_3}
C
H
3
CHOHC
H
3
→
C
u
\xrightarrow{\mathrm{Cu}}
Cu
C
H
3
C
O
C
H
3
\mathrm{CH_3COCH_3}
C
H
3
COC
H
3
→
Fehling solution
\xrightarrow{\text{Fehling solution}}
Fehling solution
No reaction
(d)
C
H
3
C
H
2
C
H
2
O
H
\mathrm{CH_3CH_2CH_2OH}
C
H
3
C
H
2
C
H
2
OH
or
C
H
3
C
H
O
H
C
H
3
\mathrm{CH_3CHOHCH_3}
C
H
3
CHOHC
H
3
→
Conc.
H
2
S
O
4
\xrightarrow{\text{Conc. } \mathrm{H_2SO_4}}
Conc.
H
2
S
O
4
C
H
3
C
H
=
C
H
2
\mathrm{CH_3CH=CH_2}
C
H
3
CH
=
C
H
2
© examsnet.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
Prev Question
Next Question
More Free Exams
AIEEE Previous Papers
BITSAT Exam Previous Papers
JEE Adv
JEE Advanced Model Papers
JEE Advanced Previous Papers
JEE Main
JEE Main PYQ
JEE Mains Model Papers
