Given a, b, c are in A.P.∴ 2b = a + c.....(i)Now, x+1x+2x+3x+2x+3x+4x+ax+bx+c [Applying R2→2R2]=21x+12x+4x+3x+22x+6x+4x+a2x+2bx+c=21x+12x+4x+3x+22x+6x+4x+a2x+(a+c)x+c[using equation (i)]=21x+10x+3x+20x+4x+a0x+c=0[Applying R2→R2−(R1+R3) ]