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WBJEE 2012 Chemistry Solved Paper
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© examsnet.com
Question : 10
Total: 40
58.4 g of NaCl and 180 g of glucose were separately dissolved in 1000mL of water. Identify the correct statement regarding the elevation of boiling point (b.p) of the resulting solutions
NaCl solution will show higher elevation of boiling point
Glucose solution will show higher elevation of boiling point
Both the solutions will show equal elevation of boiling point
The boiling point elevation will be shown by neither of the solutions
Validate
Solution:
Elevation in boiling point,
Δ
T
b
=
i
×
K
b
×
m
Molality of NaCl solution
=
n
W
×
1000
=
58.5
58.5
W
H
2
O
×
1000
=
1000
W
H
2
O
Molality of
C
6
H
12
O
6
solution
=
180
180
×
1000
W
H
2
O
=
1000
W
H
2
O
Both the solutions have same molarity but the values for NaCl and glucose are 2 and 1 respectively.
∴
∆
T
b
(
N
a
C
l
)
=
2
×
∆
T
b
(
C
6
H
12
O
6
)
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