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WBJEE 2012 Math Solved Paper
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© examsnet.com
Question : 56
Total: 80
The eccentric angle in the first quadrant of a point on the ellipse
x
2
10
+
y
2
8
=
1
at a distance 3 units from the centre of the ellipse is
π
6
π
4
π
3
π
2
Validate
Solution:
Let
P
(
√
10
cos
θ
,
√
8
sin
θ
)
be the required point on
x
2
10
+
y
2
8
=
1
Whose distance from centre (0, 0) is 3 units
∴
10
cos
2
θ
+
8
sin
2
θ
=
9
=
9
(
sin
2
θ
+
cos
2
θ
)
⇒
tan
2
θ
=
1
⇒
θ
=
π
4
© examsnet.com
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