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WBJEE 2013 Math Solved Paper
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© examsnet.com
Question : 64
Total: 80
If
s
i
n
2
θ + 3cosθ = 2 , then
c
o
s
3
θ +
s
e
c
3
θ is
1
4
9
18
Validate
Solution:
C
o
s
2
θ − 3Cosθ +1= 0 or, Cosθ +
1
c
o
s
θ
= 3
C
3
+
1
C
3
+ 3C
1
C
(
C
+
1
C
)
= 27 or
c
o
s
3
θ +
s
e
c
3
θ + 3.3 = 27
c
o
s
3
θ +
s
e
c
3
θ = 18
© examsnet.com
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