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WBJEE 2013 Physics Solved Paper
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© examsnet.com
Question : 34
Total: 60
An alternating current in a circuit is given by I = 20 sin (100πt + 0.05π) A. The r.m.s. value and the frequency of currentrespectively are
10A & 100 Hz
10A & 50 Hz
10
√
2
A & 50Hz
10
√
2
A & 100 Hz
Validate
Solution:
I = 20sin (100 πt + 0.05π)
∴
I
rms
=
20
√
2
= 10
√
2
w = 100π ⇒ f = 50 Hz
© examsnet.com
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