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WBJEE 2014 Maths Solved Paper
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© examsnet.com
Question : 55
Total: 80
The function f(x) = a sin|x| + b
e
|
x
|
is differentiable at x = 0 when
3a + b = 0
3a – b = 0
a + b = 0
a – b = 0
Validate
Solution:
f(x) = a sin|x| + b
e
|
x
|
f(x) = a sinx + b
e
x
x ≥ 0
= –a sinx + b
e
–
x
x < 0
f′(x) = acosx + b
e
x
x ≥ 0
= –acosx – b
e
–
x
x < 0
at x = 0
a + b = – a – b
a + b = 0
© examsnet.com
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