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WBJEE 2014 Maths Solved Paper
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© examsnet.com
Question : 67
Total: 80
The equation of hyperbola whose coordinates of the foci are (±8, 0) and the length of latus rectum is 24 units, is
3
x
2
-
y
2
= 48
4
x
2
-
y
2
= 48
x
2
- 3
y
2
= 48
x
2
- 4
y
2
= 48
Validate
Solution:
ae = 8
2
b
2
a
= 24
a
2
e
2
=
a
2
+
b
2
or,
64 =
a
2
+ 12a so a = 4,
b
2
= 48
x
2
16
−
y
2
48
= 1 so 3
x
2
-
y
2
= 48
© examsnet.com
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