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WBJEE 2015 Math Solved Paper
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© examsnet.com
Question : 22
Total: 80
A particle starts moving from rest from a fixed point in a fixed direction. The distance s from the fixed point at a timet is given by s =
t
2
+ at – b + 17, where a, b are real numbers. If the particle comes to rest after 5 sec at a distanceof s = 25 units from the fixed point, then values of a and b are respectively
10, -33
-10, -33
-8, 33
-10, 33
Validate
Solution:
[
d
s
d
t
]
t
=
5
=
[
2
t
+
a
]
t
=
5
= 0
⇒ a = -10
and 25 =
5
2
+ 5a - b 17 (s = 25 , t = 5)
⇒ b = -33
© examsnet.com
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