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WBJEE 2015 Math Solved Paper
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© examsnet.com
Question : 39
Total: 80
The value of λ for which the straight line
x
−
λ
3
=
y
−
1
2
+
λ
=
z
−
3
−
1
may lie on the plane x – 2y = 0 is
2
0
−
1
2
There is no such λ
Validate
Solution:
The line must be perpendicular to the normal to plane.
3.1 + (2 + λ) (–2) + (–1).0 = 0
λ =
−
1
2
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