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WBJEE 2015 Math Solved Paper

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Question : 64

Total: 80

Let f : N → R be such that f(1) = 1 andf(1) + 2f(2) + 3f(3) + ... ..... + nf(n) = n(n + 1)f(n), for all n ∊ N, n ≥ 2, where N is the set of natural numbers and R is theset of real numbers. Then the value of f(500) is

1000
500
1/500
1/1000

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