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WBJEE 2016 Math Solved Paper
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© examsnet.com
Question : 10
Total: 75
The equation of a line parallel to the line 3x + 4y = 0 and touching the circle
x
2
+
y
2
=
9
in the first quadrant is
3x + 4y = 15
3x + 4y = 45
3x + 4y = 9
3x + 4y = 27
Validate
Solution:
Let, the equation be 3x + 4y = k
then, y =
−
3
4
x
+
k
4
. By condition of tangency
(
k
4
)
2
= 9
(
1
+
(
−
3
4
)
2
)
⇒ k = ±15
3x + 4y = 15 touches in the first quadrant.
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