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WBJEE 2016 Physics Solved Paper
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© examsnet.com
Question : 37
Total: 40
A charged particle of mass
m
1
and charge
q
1
is revolving in a circle of radius r. Another charged particle of charge
q
2
and mass
m
2
is situated at the centre of the circle. If the velocity and time period of the revolving particle be v and T respectively,then
v
=
√
q
1
q
2
r
4
π
ε
0
m
1
v
=
1
m
1
√
q
1
q
2
4
π
ε
0
r
T
=
√
16
π
3
ε
0
m
1
2
r
3
q
1
q
2
T
=
√
16
π
3
ε
0
m
2
r
3
q
1
q
2
None of the above
Validate
Solution:
None of the given options are correct
Both charges are either both positive or both negative(since answers has the product
q
1
q
2
inside square root).Hence circular motion is not possible. Thus question is wrong. Either
q
1
or
q
2
should be negative
m
1
v
2
r
=
1
4
π
ε
0
m
1
q
1
q
2
r
V
=
√
1
4
π
ε
0
m
1
q
1
q
2
r
by V = rω and ω =
2
π
T
, we can find out
T
=
√
16
π
3
ε
0
m
1
r
3
q
1
2
Hence none answer is correct
© examsnet.com
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